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Answer -: Two point charges 4Q, Q are separated by 1 m in air. At what point on the line joining the charges is the electric field intensity zero? Also calculate the ...
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Jack is really caught in an ugly middle position because he is divided into two different difficult situations. He is unable to run away from the harsh realities of life rather he has to acclimatise himself in accordance with the prevailing conditions. He has to manage his family consisting of two children, a daughter Jo and her brother Bobby. Thus, Jack is entangled in two worlds. The first world belongs to Roger Fish, Roger Squirrel or Roger Chipmunk. He is telling the story of a wise owl and the Wizard with a magic wand.
The world upstairs consists of his children, Jo and Jack. Jo has rai
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The β-decay of Ne1023 may be represented as:            Ne1023 → Na1123 - e-10 + v¯ + Q Ignoring the rest mass of antineutrino v¯ and electron , we get Mass defect,                                      ∆m = m(Ne1023) - m (Na1123)         = 22.994466 - 22.989770          = 0.004696 u          ∴  Q = 0.004696×931 MeV = 4.372 MeV. This energy of 4.3792 MeV, is shared by e- and v¯ pair because, Na1123 is very massive.The maximum K.E. of e- = 4.372 MeV, when energy carried by v¯ is zero.
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Consider a potentiometer wire of length L and resistance r are connected in series to a battery of emf Eo and a resistance r1as shown in a  figure.Current in wire AB = Eo/r1 +r
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Potential difference (drop) between two cities = 150 x 8 = 1200 VAverage resistance of total wire = 0.5 x 150 = Power loss, P =                    = 19.2 kW
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2,3-Dimethyl-2-butene can be prepared by heating which of the following compounds with strong acid? (1) (CH3)2C=CH–CH2–CH3. (2) (CH3)2CH–CH–CH=CH2. (3) (CH3)2CH–(CH3)CH–CH=CH2.
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For a first order reactiont=2.303klogaa-xHere initial concentration, a = 10 g and concentration left after time t sec = 2.5 g i.e., 2.5 g i.e., (a – x) = 2.5 g.Specific reaction constant k = 10–3 sec–1.∴ Time required for the reactant to reduce to= 2.30310-3×log102.5= 2.30310-3log 4= 2.30310-3×0.6021 = 1386.6 sec.